Question

a) In the picture below, the 3 charges Q1, Q2 and Q3 are located at positions (-a,0), (a,0) and (0,-d) respectively. (The origin is the point halfway between Q1 and Q2.) Consider the special case where Q1, Q3 greater than zero and Q2 = -Q1. Select true or false for each statement. The force on Q3 due to the other two charges is zero. The electric potential at any point along the y-axis is positive. If Q3 is released from rest, it will initially accelerate to the right. The work required to move Q3 from its present position to the origin is zero. The electric field at the origin points solely in the positive y direction. The electric potential at the origin equals Q3/(4πε0d). (Here k = 1/(4πε0)) The external work done to bring these charges to this configuration (from infinity) was positive. Tries 0/6 b) In the previous problem, let Q1=1.70 μC, Q2=-2.60 μC, and Q3=4.60 μC. (Note that Q1 and Q2 are different now.) The distances are a=1.20 cm and d=2.80 cm. Calculate the potential energy of the charge configuration

Problem 6 a) In the picture below, the 3 charges Q1, Q2 and Q3 are located at positions (-a,0), (a,0) and (0,-d) respectively (The origin is the point halfway between Q1 and Q2.) 3 Consider the special case where QiQ3 greater than zero and Q2Q1 Select true or false for each statement The force on Q3 due to the other two charges is zero The electric potential at any point along the y-axis is positive If Q3 is released from rest, it will initially accelerate to the right. The work required to move Q3 from its present position to the origin is zero The electric field at the origin points solely in the positive y direction The electric potential at the origin equals Q3/(4TEod) (Here k-1/(4JtEo)) The external work done to bring these charges to this configuration (from infinity) was positive Submit Answer Tries 0/6 b) In the previous problem, let Q,-1.70 pC, Q2-2.60 pC and Q,-4.60 pC (Note that Q1 and Q2 are different now.) The distances are a=1.20 cm and d=2.80 cm Calculate the potential energy of the charge configuration

Answer 1

" ""False"" the force on Q3 due to the other two charges is zero. because y component of electric force on Q3 due to Q1 and Q2 will cancel out but x components will add up so there will be some resultant force ""True"" the electric potential at any point along the y axis is positive. Because potential due to Q1 and Q2 will cancel out on y axis but there will be potential due to Q3 which is positive charge ""True"" If Q3 is released from rest, it will initially accelerate to the right Net force on Q3 Is along + x axis at this point ""True"" the work required to move Q3 from its present position to the origin is zero. As net force is along x axis, it is not along y axis so there will be no work done to move the charge Q3 along y axis ""True"" electric field due to Q1 and Q2 will cancel out at the origin"

Answer 2

the electric field does not solely point in the y-direction. If you place a test positive charge it'll move right so there's an electric field from + to -