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Part A The volume of 350 mL of gas at 25°C is decreased to 150 mL at constant pressure. What is the final temperature of the
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Part (A):- It is given that, (25 273) K = 298 K Initial temperature (T1) 25 °C Final temperature (T2) ? Initial volume (V1) 3Then from equation (1), we have (Vi V2) (T1 /T2) = (350 mL 150 mL) (298 K / T2) or (T2 298 K) (150 mL 350 mL) 0.43 T2 0.43 xor T2 (128.14 273) °C = -144.86 °C or final temperature (T2) = -145 °C So, the correct option will be (d) -145 °C

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