Question

Asample of methane (CH4) has a volume of 21 mL at a pressure of 1.5 atm. What is the final volume, in milliliters, of the gas

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Answer #1

A)

Given:

Vi = 21 mL

Pi = 1.5 atm

Pf = 0.20 atm

use:

Pi*Vi = Pf*Vf

1.5 atm * 21 mL = 0.2 atm * Vf

Vf = 158 mL

Answer: 160 mL

B)

Given:

Vi = 21 mL

Pi = 1.5 atm

Pf = 2.67 atm

use:

Pi*Vi = Pf*Vf

1.5 atm * 21 mL = 2.67 atm * Vf

Vf = 12 mL

Answer: 12 mL

C)

Given:

Vi = 21 mL

Pi = 1.5 atm

Pf = 2900.0 mm Hg

= (2900.0/760) atm

= 3.8158 atm

use:

Pi*Vi = Pf*Vf

1.5 atm * 21 mL = 3.8158 atm * Vf

Vf = 8.3 mL

Answer: 8.3 mL

D)

Given:

Vi = 21 mL

Pi = 1.5 atm

Pf = 89.0 torr

= (89.0/760) atm

= 0.1171 atm

use:

Pi*Vi = Pf*Vf

1.5 atm * 21 mL = 0.1171 atm * Vf

Vf = 269 mL

Answer: 270 mL

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