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Calculate the final pressure, in millimeters of mercury, for each of the following, if volume and amount of gas do not change

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Answer #1

Assuming ideal behaviour we know that for a gas if pressure is P, temperature (in K) is T ;then P is directly proportional to T

a) T1=1580C = 431K, T2= 00C = 273K

so P​​​​​1​​​​​/P​​​​​​2=T​​​​​1/T 2

Here P​​​​​​1= 1400 torr = 1400 mm Hg

Hence P2 = 1400*273/431 = 8.9* 102 mm Hg= 1.2 atm

b) here P1= 1.4 atm = 1.4 * 760 mm Hg = 1064 mm Hg, T1= 150C = 288 K, T2= 311 K

So P2 =1064*311/288 = 1.15*103 mm Hg = 1.51 atm

As here mentioned about significant figure so pressure in atm unit will be more acceptable as it will match with significant no requirements.

1 torr =1 mm Hg= (1/760) atm this is the governing relation of pressure term.

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