Question

Review | Constants Periodic Table A gas sample has an initial volume of 642 mL, an initial temperature of 30.0°C, and an initial pressure of 735 mm Hg The volume is decreased to 43.4 ml and the temperature is increased to 60.00 Part A What is the final pressure? 248 mm Hg 2.17 x 10 mm Hg 1190 mm Hg 544 mm Hg Submit Request Answer assignment problemi ADG 104 PM ANG 3/25/2020 Orte 9

Answer 1

Solution : (1190 mm Hg)

Calculation :

According to ideal gas equation,

P1V1/T1 = P2V2/T2

P2 = P1V1T2 / T1V2

Given,

P1 = initial pressures = 735 mm Hg

V1 = initial volume = 64.2 mL

T1 = 30 °C = 30 + 273 = 303 K

P2 = final pressure = ?

V2 = final volume = 43.4 mL

T2 = final temperature = 60 °C = 60 + 273 = 333 K

Therefore,

P2 = P1 V1 T2 / V2 T1

P2 = 735 mm Hg x 64.2 mL x 333 K / 43.4 mL x 303 K

P2 = 1194.09 mm Hg

P2 = 1190 mm Hg