"A student in another class made a claim that many people are now talking about outlawing...
"A student in another class made a claim that many people are now talking about outlawing the use of cigarettes. You want to estimate that proportion and ask a random sample of 200 people whether they are in favor of outlawing cigarettes. Of the 200 people, 27% are in favor. Using α=.05, which means 95% confidence,write a confidence statement for the true population proportion.
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"A student in another class made a claim that many people are
now talking about outlawing...
2. Suppose that a random sample of 41 state college students is asked to measure the...
2. Suppose that a random sample of 41 state college students is asked to measure the length of their right foot in centimeters. A 90% confidence interval for the mean foot length for students at this university turns out to be (21.709, 25.091). If we now calculated a 95% confidence interval, would the new confidence interval be wider than or narrower than or the same as the original? b. Suppose two researchers want to estimate the proportion of American college...
Example 5: Another made up report ("Stat 1x1 Student Ages") claimed that, "The age of University ...
Can anyone explain where the 252 came from for the
hypotheses?
Example 5: Another made up report ("Stat 1x1 Student Ages") claimed that, "The age of University of Alberta Stat 1x1 students depends on gender." To explore this claim, a poll was conducted by a particular statistics instructor. The results found the following Summary statistics for age (in months): Variance 243.5 2620.582 240.5 1729.273 Mean Std. Dev. gen Female Male 74 51.192 52 41.585 Assuming the individuals were randomly selected...
Option 1 or 2 Option 1: Think about a population mean that you may be interested...
Option 1 or 2
Option 1: Think about a population mean that you may be interested in and propose a confidence interval problem for this parameter. Your data values should be approximately normal. For example, you may want to estimate the population mean number of times that adults go out for dinner each week. Your data could be that you spoke with seven people you know and found that they went out 2, 0, 1, 5, 0, 2, and 3...
Question 17 (1 point) Let's say that i take our class to be a SRS and...
Question 17 (1 point) Let's say that i take our class to be a SRS and gather data on everyone's weight. Taking that sample we see that our sample mean is 68 kilograms. Assume that we magically know that the true population standard deviation is 10 kilograms. Based on our data, gathered from 40 students, can you give me an estimate on the true population mean weight? Give me a 95% Confidence interval O (64.9,71.1) (66.4, 69.92) (62, 74.2) (58.1,...
1. A popular claim, nicknamed "feshman fifteen," states that many college students gain weight point) in...
1. A popular claim, nicknamed "feshman fifteen," states that many college students gain weight point) in their freshman year. You are given the 95% confidence interval as 559% <P < 78 4% Correctly interpret the interval. There is a 95% chance tha the true percentage of college freshmen who gain weight is between 559% and 78 496. 95% of sample college freshmen who gain weight will fall between 55.9% and 78 4% We are confident that 95% of college freshmen,who...
3 (40) omedical study, people are interested in a gene A's expression. Now e a random sample of size N 90 different people from the study sample mean is 80, sample standard deviation is s-27....
3 (40) omedical study, people are interested in a gene A's expression. Now e a random sample of size N 90 different people from the study sample mean is 80, sample standard deviation is s-27. Assume μ'ơn No calculations needed, just specify the variables correctly and . Researchers believed the mean value should only be Ho 70. They are the parameters of the study. 2. 1.64, 20.05/2-1.96 0.05 write down the correct fomulas. want to show whether this gene A...
Assume an approximate normal distrihution. IS. A random sample of 12 eniployees of the Wlergate Carpet...
Assume an approximate normal distrihution. IS. A random sample of 12 eniployees of the Wlergate Carpet Company wed an average contribution of $8.00 to the American Cancer Socicty, with a landard deviation of $1.25, Construct u 90% wnfidence interva: for the average contribution by all employces of the Watergate Carpet Company to the American Cancer Society. Assume the contribuions to hc?pproxi- matcly normally distributed. Suction 8.5 16. (a) A random sample of 200 voters from Salem, Virginia, is selected and...
Suppose that students own an average of 4 pairs of jeans. 8 people from your class were surveyed to determine if the ave...
Suppose that students own an average of 4 pairs of jeans. 8 people from your class were surveyed to determine if the average for students in college is higher than 4. DATA TO USE: 3, 4, 4, 5, 5, 5, 7, 12 A) In words, CLEARLY state what your random variable X or P' represents. B) State the distribution to use for the test. If t, include the degrees of freedom. If normal, include the mean and standard deviation. C)...
н Select one answer 10 points Parking survey: For a class assignment, a group of statistics...
н Select one answer 10 points Parking survey: For a class assignment, a group of statistics students set up a table near the student parking lot. They asked students who passed by to complete a quick survey about whether they support the building of a multi- level parking structure that would add 425 new spaces at the college. They used the information from the survey to calculate the 95% confidence interval: (0,53, 0.72). To which population does the confidence interval...
It is difficult to conduct sample surveys on sensitive issues because many people will not answer...
It is difficult to conduct sample surveys on sensitive issues
because many people will not answer questions if the answers might
embarrass them. Randomized response is an
effective way to guarantee anonymity while collecting information
on topics such as student cheating or sexual behavior. Here is the
idea. To ask a sample of students whether they have plagiarized a
term paper while in college, have each student toss a coin in
private. If the coin lands heads and they have...
2. Suppose that a random sample of 41 state college students is asked to measure the length of their right foot in centimeters. A 90% confidence interval for the mean foot length for students at this university turns out to be (21.709, 25.091). If we now calculated a 95% confidence interval, would the new confidence interval be wider than or narrower than or the same as the original? b. Suppose two researchers want to estimate the proportion of American college...
Can anyone explain where the 252 came from for the
hypotheses?
Example 5: Another made up report ("Stat 1x1 Student Ages") claimed that, "The age of University of Alberta Stat 1x1 students depends on gender." To explore this claim, a poll was conducted by a particular statistics instructor. The results found the following Summary statistics for age (in months): Variance 243.5 2620.582 240.5 1729.273 Mean Std. Dev. gen Female Male 74 51.192 52 41.585 Assuming the individuals were randomly selected...
Option 1 or 2
Option 1: Think about a population mean that you may be interested in and propose a confidence interval problem for this parameter. Your data values should be approximately normal. For example, you may want to estimate the population mean number of times that adults go out for dinner each week. Your data could be that you spoke with seven people you know and found that they went out 2, 0, 1, 5, 0, 2, and 3...
Question 17 (1 point) Let's say that i take our class to be a SRS and gather data on everyone's weight. Taking that sample we see that our sample mean is 68 kilograms. Assume that we magically know that the true population standard deviation is 10 kilograms. Based on our data, gathered from 40 students, can you give me an estimate on the true population mean weight? Give me a 95% Confidence interval O (64.9,71.1) (66.4, 69.92) (62, 74.2) (58.1,...
1. A popular claim, nicknamed "feshman fifteen," states that many college students gain weight point) in their freshman year. You are given the 95% confidence interval as 559% <P < 78 4% Correctly interpret the interval. There is a 95% chance tha the true percentage of college freshmen who gain weight is between 559% and 78 496. 95% of sample college freshmen who gain weight will fall between 55.9% and 78 4% We are confident that 95% of college freshmen,who...
3 (40) omedical study, people are interested in a gene A's expression. Now e a random sample of size N 90 different people from the study sample mean is 80, sample standard deviation is s-27. Assume μ'ơn No calculations needed, just specify the variables correctly and . Researchers believed the mean value should only be Ho 70. They are the parameters of the study. 2. 1.64, 20.05/2-1.96 0.05 write down the correct fomulas. want to show whether this gene A...
Assume an approximate normal distrihution. IS. A random sample of 12 eniployees of the Wlergate Carpet Company wed an average contribution of $8.00 to the American Cancer Socicty, with a landard deviation of $1.25, Construct u 90% wnfidence interva: for the average contribution by all employces of the Watergate Carpet Company to the American Cancer Society. Assume the contribuions to hc?pproxi- matcly normally distributed. Suction 8.5 16. (a) A random sample of 200 voters from Salem, Virginia, is selected and...
н Select one answer 10 points Parking survey: For a class assignment, a group of statistics students set up a table near the student parking lot. They asked students who passed by to complete a quick survey about whether they support the building of a multi- level parking structure that would add 425 new spaces at the college. They used the information from the survey to calculate the 95% confidence interval: (0,53, 0.72). To which population does the confidence interval...
It is difficult to conduct sample surveys on sensitive issues
because many people will not answer questions if the answers might
embarrass them. Randomized response is an
effective way to guarantee anonymity while collecting information
on topics such as student cheating or sexual behavior. Here is the
idea. To ask a sample of students whether they have plagiarized a
term paper while in college, have each student toss a coin in
private. If the coin lands heads and they have...
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