Question

1. A popular claim, nicknamed feshman fifteen, states that many college students gain weight point) in their freshman year. You are given the 95% confidence interval as 559% <P < 78 4% Correctly interpret the interval. There is a 95% chance tha the true percentage of college freshmen who gain weight is between 559% and 78 496. 95% of sample college freshmen who gain weight will fall between 55.9% and 78 4% We are confident that 95% of college freshmen,who gain weight gain 55.9% to 78 4% of the weight of all college freshmen o we are 95% confident that the interval from 55.9% to 78.4% actually does contain the true percentage of college freshmen who gain weight 2. How many randomly selected adults must be surveyed to estimate the percentage of adults in (lpoint) the country who now use the Internet? Assume that you want to be 99% confident that the sample percentage is within 2 percentage points of the true population percentage and that you know nothing about the percentage of adults using the Internet 16,577 4.145 2.401 613
(1 point) 3. Use a sample n = 500, p = 090, and a 95% confidence level to construct a confidence interval estimate of the population proportion, p 00.878 <p0.922 0.874<p<0.926 00887 <p < 0.913 00.817 <p0.983 4. Find the critical value corresponding to an 80% confidence level. (1 point) О 1.28 01.645 0.20 1.96 E5. Find the o2 for a 0.01. ( point) 2.575 0.01 1.96 1.645
0 0
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Answer #1

1)
option D) is correct

2)
n = z^2/(4 e^2)
= (2.576/(2*0.02))^2
=4147

option B) 4145 is correct

3) 95 % CI
(0.873704, 0.926296)

option B) is correct
4)
A) 1.28 is correct

5)

A)2.575

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