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6. How many randomly selected adults must be surveyed to estimate the percentage of adults in ( point) the country who now use the Internet? Assume that you want to be 99% confident that the sample percentage is within 2 percentage points of the true population percentage and that you know nothing about the percentage of adults using the Internet. 16,577 O 4,145 O 2,401 O 613 (l point 7-A recent poll of 1800 people showed that 35% believe gas prices will go down. Find the best point estimate of the proportion of all people who believe gas prices will go down. 0 35 O 0.30 O 0.65 0.35 8. Find the critical value za2 corresponding to a 99.5% confidence level. a point) 0.0025 2.81 O 1.96 2.575 apomo Given n-875 and p-045, find the margin of error E that corresponds to a 95% confidence
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6. How many randomly selected adults must be surveyed to estimate the percentage of adults in ( point) the country who now use the Internet? Assume that you want to be 99% confident that the sample percentage is within 2 percentage points of the true population percentage and that you know nothing about the percentage of adults using the Internet 16,577 4,145 n = 0.5(1-0.5)( 2.576 0.02 O 2,401 613 7, A recent poll of 1800 people showed that 35% believe gas prices will go down. Find the best (l point point estimate of the proportion of all people who believe gas prices will go down. 0 35 O 0.30 0.65 P-0.35 8. Find the critical value za2 corresponding to a 99.5% confidence level. a point) 0.0025 281 1.96 2.575 a pomo 9. Given n-875 and卢-045, find the margin of error E that corresponds to a 95% confidence

O 0.65 0.35 8. Find the critical value zu? corresponding to a 99.5% confidence level. (1 point) 0 0.0025 2.81 O 196 2.575 (Pom) 9. Given n-875 and β-0.45, find the margin of error E that corresponds to a 95% confidence level. 00.001 00.016 0.044 0.033 0.25(1-0.232-0.033 1.96 875 truct a confidence interval (1 point) -0.25, and a 90 % confidence level to cons 10. Use a sample n = 840, estimate of the population proportion, p 0.225<p < 0.275 02370263 0.25-1.645025(4-0.25) 00221 <p< 0.279 o 0214 <p02860.225 < p <0.27:5 8400.25+1.645, 0251-025) 840 Finish Cancel

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