To understand two different techniques for computing the torque on an object due to an applied force. Imagine an object with a pivot point p at the origin of the coordinate system shown (Figure 1). The force vector F⃗ lies in the xy plane, and this force of magnitude F acts on the object at a point in the xy plane. The vector r⃗ is the position vector relative to the pivot point p to the point where F⃗ is applied. The torque on the object due to the forceF⃗ is equal to the cross product τ⃗ =r⃗ ×F⃗ . When, as in this problem, the force vector and lever arm both lie in the xy plane of the paper or computer screen, only the z component of torque is nonzero. When the torque vector is parallel to the z axis (τ⃗ =τk^), it is easiest to find the magnitude and sign of the torque, τ, in terms of the angleθ between the position and force vectors using one of two simple methods: the Tangential Component of the Forcemethod or the Moment Arm of the Force method. Note that in this problem, the positive z direction is perpendicular to the computer screen and points toward you (given by the right-hand rule i^×j^=k^), so a positive torque would cause counterclockwise rotation about thez axis. | Tangential component of the force Part A (Figure 2) Enter your answer as an ordered pair. Express Ft and Fr in terms of F and θ. Hint 1. Magnitude of F⃗ ropened hint Use the given angle between the force vector F⃗ and its radial component F⃗ r to compute the magnitudeFr. (Fr,Ft)=nothingPart B Is the following statement true or false? The torque about point p is proportional to the length of the position vector .truefalse Part C Is the following statement true or false? Both the radial and tangential components of generate torque about point p.truefalse Part D Is the following statement true or false? In this problem, the tangential force vector would tend to turn an object clockwise around pivot point p.truefalse Part E Find the torque τ about the pivot point p due to forceF⃗ . Your answer should correctly express both the magnitude and sign of τ. Express your answer in terms of Ft and r or in terms of F, θ, and r. τ=nothingMoment arm of the force In the figure, the dashed line extending from the force vector is called the line of action of F⃗ . The perpendicular distance rm from the pivot point p to the line of action is called the moment arm of the force. Part F (Figure 3) Express your answer in terms of r and θ. rm=nothingPart G Find the torque τ about p due to F⃗ . Your answer should correctly express both the magnitude and sign ofτ. Express your answer in terms of rm and F or in terms of r, θ, and F. τ=nothing |
A pivot point p at the origin of the xy plane is shown in the figure. The vector r is the position vector relative to the pivot point p to the point where force F is applied. Vector r lies in the first quadrant. Vector F starts from the end of r and is directed downward and to the right. The acute angle between F and straight line containing r is labeled theta. The perpendicular distance from point p to the line of action of F is labeled as r m. A positive torque would cause counterclockwise rotation about the z-axis perpendicular to the plane of the figure. |
To understand two different techniques for computing the torqueon an object due to an applied...
A force F⃗ of magnitude F making an angle θ with the x axis is applied to a particle located along axis of rotation A, at Cartesian coordinates (0,0) in the figure. The vector F⃗ lies in the xy plane, and the four axes of rotation A, B, C, and D all lie perpendicular to the xy plane. A particle is located at a vector position r⃗ r→r_vec with respect to an axis of rotation (thus r⃗ r→r_vec points from...
To understand the two most common procedures for finding torques when the forces and displacements are all in one plane: the moment arm method and the tangential force method. The purpose of this problem is to give you further practice finding torques in two-dimensional situations. In this case it is overkill to use the full cross product definition of the torque because the only nonzero component of the torque is the component perpendicular to the plane containing the problem. There...
The tangential force method involves finding the component of theapplied force that is perpendicular to the displacement from thepivot point to where the force is applied. This perpendicularcomponent of the force is called the tangential force. (a) What is , the magnitude of the tangential forcethat acts on the pole due to the tension in the rope? Express your answer in terms of and . When using the tangential force method, you calculate the torqueusing the equation , where is...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 6.39 N )i +( -3.16 N )j is applied to the bar at the point x = 2.29 m, y = 3.19 m.A) What is the position vector r⃗ for the point where the force is applied?Enter the x and y components of the radius vector separated by a comma.*B) What is the magnitude of the torque with respect to...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F⃗ =( 6.22 N )i^+( -2.81 N )j^ is applied to the bar at the point x= 3.58 m , y= 3.46 m . Part A: What is the position vector r⃗ for the point where the force is applied? Enter the x and y components of the radius vector separated by a comma. Part B: What are the magnitude of the...
A metal bar is in the xy-plane with one end of the bar at the origin. A force F⃗ =( 6.67 N )i^+( -2.62 N )j^ is applied to the bar at the point x= 2.60 m , y= 3.00 m . Part A What is the position vector r⃗ for the point where the force is applied? Enter the x and y components of the radius vector separated by a comma. Part B What are the magnitude of the...
Write the expression for the magnitude of the torque τ about a point O due to a force F with arrow applied at distance r with arrow from O and the angle between the two vectors is θ. (Use the following as necessary: F, r, and θ.)
A force, = (6 + 3 ) N, is applied to an object at a point whose position vector with respect to the pivot point is = (5 + 4 + 3 ) m. Calculate the torque (in units on Nm) created by the force about that pivot point. A) Tx = B) τy = C) τz =
Mail A A wrench 40 cm long lies along the positive y-axls and grips a bolt at the origin. A force is applied in the direction (0, 4,-3) at the end of the wrench. Find the magnitude of the force needed to supply 90 N·m of torque to the bolt Stop 1 The magnitude of the torque τ developed by applying a force F at a point with position vector r at an angle θ to r is given by...
An object moves in a circular path with constant angular speed. Compare the direction of the object's tangential velocity vector to its centripetal acceleration vector. A) Both vectors point in the same direction B) The vectors point in opposite directions C) The vectors are perpendicular D) Impossible. The acceleration is zero. Two objects with masses m1 and m2 are original a distance r apart. The magnitude of the gravitational force between them is F. if BOTH masses are doubled, and...