Question

In the figure (Figure 1) a conducting rod of length L = 30.0 cm moves in a magnetic field B? of magnitude 0.470 T directed into the plane of the figure. The rod moves with speed v = 5.60 m/s in the direction shown. I need help with Part A,C,F,G

Answer 1

Part A

Potential Difference V = vBL = 5.60*0.470*0.30 = 0.7896 V.........Ans.

Part B

The positive charge build up at b gives a higher electric potential at b.

Part C

The electric field points from b to a, resisting further charge separation. As we showed above,

E = vB = 5.60*0.470 = 2.632 V/m........Ans.

Part D

from a to b

Part F

If the rod moves parallel to ab

Vab = EL = 0 , because the rod is thin (L ≈ 0).

Part G

If the rod moves directly out of the page FB = qv × B = 0 ,

because v and B would be in the same direction, and no charge separation occurs, so Vab = 0.