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A driver is traveling at 30.0 m>s when he sees a moose crossing the road 80.0...

A driver is traveling at 30.0 m>s when he sees a moose crossing the road 80.0 m ahead. The moose becomes distracted and stops in the middle of the road. If the driver of the car slams on the brakes, what is the minimum constant acceleration he must undergo to stop short of the moose and avert an accident?

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Answer #1

initial velocity of car = Vi = 30 m/s

final velocity = Vf =0 m/s

distance = d = 80 m

acceleration = a

using the equation ::

Vf2 = Vi2 + 2 a d

02 = 302 + 2 a (80)

a = - 5.625 m/s2

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