Question

A ball is thrown upward at a speed v0 at an angle of 52.0˚ above the horizontal

A ball is thrown upward at a speed v0 at an angle of 52.0˚ above the horizontal. It reaches a maximum height of 7.3 m. How high would this ball go if it were thrown straight upward at speed v0?
1 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1
The height is rises is proportional to (Vo*sinA)^2
Only the vertical component of velocity can be exchanged for gravitational potential energy.

Vo stays the same

The height ratio is therefore

H(90deg)/H(52deg) = (sin90/sin52)^2 = 1.610

H(90 deg) = 1.610*7.3 = 11.76 m
answered by: Shanaynay
Add a comment
Know the answer?
Add Answer to:
A ball is thrown upward at a speed v0 at an angle of 52.0˚ above the horizontal
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT