Question

A sine wave signal is displayed on the screen of an oscilloscope. 6 peak-to-peak divisions are measured vertically and 8 peak-to-peak divisions horizontally. The voltage control is on the 2 volts / div scale and the sweep control is on the 5ms scale. The signal period is:

a.

0.03 seconds
b.
0.04 seconds
c.
4 seconds
d.
0.005 seconds

Answer 1

6 peak to peak divisions (vertically)which are measured, corresponds to voltage of the signal whose amplitude can be adjusted using volt/div control.

Here voltage control is on the 2 volts /div scale.

8 peak to peak divisions (horizontally)which are measured , corresponds to time whose value can be adjusted using second/div control .

Here sweep control is on 5ms scale.

Our aim is to determine the signal period.so we only interested in 8 peak to peak divisions of wave which corresponds to the time period.

Since we have 5 ms per division,the total time period of signal is,

T=8 peak to peak divisions (horizontally)* 5 ms

T=8*(5*10^-3)

T=8*0.005

T=0.04 s

Hence signal period is 0.04 seconds

So option (b) is the correct answer .