Assuming that the situation is as I described, call the string tension T and the acceleration a
First the 10 kg mass falling
m g - T = m a
98 - T = 10 a
Now the 3.5 kg mass sliding up the incline.
T - m g sin 42 = m a
T - 43.98 = 6.7 a
add the two
98 - 43.98 = 10 a + 6.7 a
54.02 = 16.7 a
a = 54.02/16.7
plug a into the tension equation to get T
Two packing crates of masses m1 = 10.0 kg and m2 = 6.70 kg are connected by a light string that...
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