A car starts from rest at a stop sign. It accelerates at 4.0 m/s2 for 9 seconds, coasts for 4 s,...
Homework Answers
final speed after acceleration:
Vf = 0 + 4*9 = 36 m/s
distance travel during acceleration:
d = 0.5(0 + 36) * 9 = 162 m
distance travel during constant speed
d = 36 * 4 = 144 m
time taken during deceleration:
t = (0 - 9)/ -3 = 3 seconds
distance travel during deceleration:
d = 0.5 (0 + 9) * 3 = 13.5 m
total distance travel :
162 + 144 + 13.5 = 319.5 m
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