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Problem 2.19 Item 2 > Review A car starts from rest at a stop sign. It accelerates at 4.6 m/s for 6.8 s, coasts for 2.5 s, an
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sol initial velocity of car=om18 its acceleration = 4.6m18² (for t=6688) displacement (8) = ut t I a, ut? &= ox(6-8) + ļ (4.car far away from stop = 8,+82 = 106.4 +67.3 = 173.7 m If we want to write it as two significant sigure then we have to a are

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