Question

A small glass bead has been charged to 4.0 nC. What is the strength of its electric field 2.0 cm from the center of the bead?

Answer 1

Given:Charge on the bead = q = 4 nC = 4 x10^-9 Cdistance of a point from the center of the beadr = 2 cm = 0.02 mthus, Electric field due to this bead at thispoint is given by the formulaE = K q / r²where K is the electrostatic constantvalue: 9 x 10⁹ Nm² / C²thus, E = (9 x10⁹) (4 x10^-9 )/(0.02)²= 90000N /C