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A 65 kg ice skater coasts with no effort for 75 m until she stops. If the coefficient of kinetic...

A 65 kg ice skater coasts with no effort for 75 m until she stops. If the coefficient of kinetic friction between her skates and the ice is µk = 0.11, how fast was shemoving at the start of her coast?
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Answer #1

friction force=μmg

accelaration=μg

=.11*9.8

=1.078

now

v^2=u^2-2*a*s

0=u^2-2*1.078*75

u=12.716 m/s speed at the start

answered by: LOU LOU
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