F= uk fn= uk mg
ma= uk mg
a= uk g
a= 0.550(-9.8)
a=-5.39 m/s^2
(b) Vf2= Vi2+ 2 a d
0=(6.4)2+ 2 (-5.39) d
d=3.8m
Help me solving this A skater with an initial speed of 6.40 m/s stops propelling himself...
A skater with an initial speed of 3.5 m/s stops propelling himself and begins to coast across the ice, eventually coming to rest. Air resistance is negligible. If the coefficient of kinetic friction between the ice and the skate blades is 0.08, find the acceleration caused by kinetic friction.
An ice skater is gliding horizontally across the ice with an initial velocity of +6.04 m/s. The coefficient of kinetic friction between the ice and the skate blades is 0.0804, and air resistance is negligible. How much time elapses before her velocity is reduced to +2.91 m/s?