Question

Sparkling diamonds part 1: need part D calculate delta for theta.

A beam of white light is incident on the surface of a diamond at an angle theta_a. Since the index of refraction depends on the light's wavelength, the differentcolors that comprise white light will spread out as they pass through the diamond. The indices of refraction in diamond are n_red=2.410 for red light and n_blue=2.450for blue light. The surrounding air has n_air=1.000. Note that the angles in the figure are not to scale.
http://session.masteringphysics.com/problemAsset/1011242/12/95031A.jpg

A.) Calculate v_red, the speed of red light in the diamond. To four significant figures, c=2.998 10^8 m/s. It was 2.244 x 10^8 m/s.
B.) Calculate v_blue, the speed of blue light in the diamond. To four significant figures, c=2.998 x 10^8 m/s. It was 2.224 x 10^8 m/s.
C.) Derive a formula for delta, the angle between the red and blue refracted rays in the diamond.
Express the angle in terms of n_red, n_blue, and theta_a. Use n_air=1. Remember that the proper way to enter the inverse sine of x in this case is asin(x).
Answer was:
delta = asin(1/n_red x sin(theta_a)) - asin(1/n_blue x sin(theta_a))

D.) Calculate delta numerically for theta =45 degrees.
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