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Two masses, a pulley, an inclined plane

Block 1, of mass = 0.550 , is connected over an ideal (massless and frictionless) pulley to block 2, of mass , as shown. Assume that the blocks accelerate as shownwith an acceleration of magnitude = 0.600 and that the coefficient of kinetic friction between block 2 and the plane is = 0.200.

What is the mass of the second block?
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Answer #1


Given data:

m1 = 0.550 Kg

m2 = ?

Acceleration a = 0.600 m/s^2

Coefficient of kinetic friction μ = 0.200

Angle of inclination θ = 30 degrees

Equation of motion for m1

T = m1g - m1a ---------------------(1)

Equation of motion for m2

T = m2a + m2g sinθ + μm2g cosθ ---------------(2)

From (1) and (2)

m2 = m1(g-a)/[a + g sinθ + μ g cosθ]

= 5.06/7.197

= 0.7030 Kg

thereforethe mass of the second block is 0.7030 kg.


answered by: Soska
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