Question

7.HW. A bullet is fired into a block of wood sitting on a block of ice. The bullet has an initial velocity of 500m/s and a mass of 0.005kg. The wooden block has a mass of 1.2kg and is initially at rest. The bullet remains embedded in the wood afterward. (so hit and stick situation) A)Assuming that momentum is conserved, find the velocity of the block of wood and bullet after the Collision. (so momentum before = momentum. V1’=V2'=V') B)What is the magnitude of the impulse that acts on the block of wood in this process ? C)Does the change in momentum of the bullet equals that of the wood ?

Answer 1

wooden block wooden block & bles bullet. mų, U=0 According to question, we are trying to draw a preture. using conservation of linear momentum mu, + Mxo = (n +). +M Given, U, = 560 ms, m= 0.005 kg, M = 1.2kg them, v. 0.005 x 500 1.2+0.005 A & = 2.075 m/s final velocity. B). Impulse - Change of momentum. - Mem, &- mxo = (1.2 +0.005) x 2.075-0 = 2.50 Kg.mis. Change of momentum of the sullet is (MM) - mo, = 2:07X(1.2 +0.005) - 0.005x 500 = 3.15x10 Kg. nls. I No