Two positive charges q1 = q2 = 2.0 μC are located at x = 0, y...

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Two positive charges q1 = q2 = 2.0 μC are located at x = 0, y...

Two positive charges q1 = q2 = 2.0 μC are located at x = 0, y = 0.30 m and x = 0, y = -0.30 m, respectively. Third point charge Q = 4.0 μC is located at x = 0.40 m, y = 0.What is the net force ((a)magnitude and (b)direction) on charge q1 exerted by the other two charges?

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Answer 1

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The force on the first charge due to the second charge is, kq,q2 9x109 (2x10-5 (2x106 0.6 -100x109x10-12j -0.1 Nj The force o

The direction of the force is, tan θ = 0.273 -0.23 0 - tan1 0.273 -0.23 -49.89 50

9 -500 1 300

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Answer 2

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