Question

Learning Goal:

 To understand Coulomb's law, electric fields, and the connection between the electric field and the electric force.

 Coulomb's law gives the electrostatic force F acting between two charges. The magnitude F of the force between two charges q1 and q2 depends on the product of the charges and the square of the distance r between the charges:

 Part C

 If the total positive charge is Q = 1.62x10^-6 C, what is the magnitude of the electric field caused by this charge at point P, a distance d = 1.53 m from the charge? (Figure 1)

 Part D

 What is the direction of the electric field at point P? (Figure 2)

Answer 1

Since Q is a positive charge then the electric field lines will be directed towards outward

Hence the direction of electric field at point P will be towards G