The voltage across the terminals of a
9.0 V battery is 8.1 V when the battery is connected to a 40 Ω load.
What is the battery's internal resistance?
APPLY THE formula from ohms law in simple ckt
initlal current i = V/R = 8.1/40 = 0.2025 Amps
as V - E = i (R+r)
r = (9-8.1)/0.2025
r = 4.45 ohms
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