The voltage across the terminals of a 9.0V battery is 8.3V when the battery is connected to a 60? load.
What is the battery's internal resistance?
The concepts used to solve this problem are Ohm’s law and Kirchhoff’s loop rule.
Initially, the current flowing through the circuit can be calculated by using the ohm’s law equation by substituting potential and resistance. Later the internal resistance of the battery can be calculated by using Kirchhoff’s loop rule by relating the equation with emf, internal resistance, current and resistance.
At constant temperature, the steady current flow through the circuit is directly proportional to the potential developed across the circuit gives the ohm’s law.
The relation between the current and potential difference from the ohm’s law is,
Here, is the current flow through the circuit, is the voltage, andis the external load resistance.
From Kirchhoff’s loop rule, the loop equation for the internal resistance of the battery is,
Here, is the internal resistance of the battery and is the emf of the battery.
According to the ohm’s law,
The expression can be rewrite for the current flow through the circuit,
Substitute for and for to find I.
According to Kirchhoff’s loop rule, the loop equation for the internal resistance of the battery is,
The expression can be rewrite for the internal resistance of the battery,
Substitute for , for , and for to find r.
Ans:The internal resistance of the battery is .
The voltage across the terminals of a 9.0V battery is 8.3V when the battery is connected...
The voltage across the terminals of a 9.0 V battery is 8.1 V when the battery is connected to a 40 Ω load. What is the battery's internal resistance?
When a battery voltage is measured by placing a high-resistance voltmeter across the terminals of the battery, the voltmeter reads 6.3V. With the voltmeter leads still attached, the battery terminals are then connected to a resistor in series with an ammeter. In this arrangement, the ammeter reads 150 mA, and the voltmeter reads 5.9V. What are the emf and the internal resistance of the battery?
A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals as shown. The capacitor initially uncharged. At the moment the switch is closed the voltage across the capacitor is equal to the battery's terminal voltage less than the battery's terminal voltage, but greater than zero. equal to the battery's terminal voltage zero.
1. The terminals of a 0.70 V watch battery are connected by a 130-m-long gold wire with a diameter of 0.100 mm . What is the current in the wire? Express your answer using three significant figures in mA 2. A waterbed heater uses 500 W of power. It is on 35 % of the time, off 65 % .What is the annual cost of electricity at a billing rate of $0.12 per kWhr? Express your answer using two significant...
A: When a 20 om resistor is connected across the terminals of a 12 V battery, the terminal voltage of the battery falls to 10 V. What is the internal resistance of the battery? C: The capacitor is initially uncharged. When the switch is closed to "a", current starts to flow.V=20.0V, C=1.02 muF If the current from the battery is initially 0.2 A, what is the time constant for this RC circuit? (Answer in seconds)
3. (10 pts) A 1.5V battery produces 45 mA when it is across a 30.0 22 load. (a) Find the potential difference across the battery's terminals. (b) What is the battery's internal resistance?
A voltmeter is connected across the terminals of a 15.0 V battery and a 75 ohm appliances connected across its terminals. If the voltmeter reads 11.3 V How much power is dissipated by the appliance? What is the internal resistance of the battery?
In circuit A, a resistor of resistance R is connected across the terminals of a battery with no internal resistance. In circuit B, an identical resistor is connected across a battery which is identical to the battery in the other circuit, except it has internal resistance r. 75.0% less power is dissipated in the resistor in circuit B than the resistor in circuit A. Determine the ratio r/R. Remember to express the answer with three significant digits.
With a 1500 MΩ resistor across its terminals, the terminal voltage of a certain battery is 2.63 V . With only a 5.10 Ω resistor across its terminals, the terminal voltage is 1.72 V . Part A) Find the internal emf of this battery. Part B) Find the internal resistance of this battery. Part C) What would be the terminal voltage if the 5.10 Ω resistor were replaced by a 7.10 Ω resistor?
With a 1600 MΩ resistor across its terminals, the terminal voltage of a certain battery is 2.64 V . With only a 5.12 Ω resistor across its terminals, the terminal voltage is 1.81 V What would be the terminal voltage if the 5.12 Ω resistor were replaced by a 7.12 Ω resistor? Find the internal resistance of this battery