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Three particles of masses m1=1.2 kg, m2=2.5kg, and m3=3.4kg form an equilateral triangle of edge...

Three particles of masses m1=1.2 kg, m2=2.5kg, and m3=3.4kg form an equilateral triangle of edge length a=140 cm. Where is the center of mass of this system?
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Im (0,0) (a,0) The center of mass of the system is, m (0)+m (a) 2 m, m +m 2 140x10m (3.4 kg (2.5 kg) (140x10 m)+(3.4 kg) 140x10 m 2 2 1.2 kg +2.5 kg +3.4 kg 1.2 kg 2.5 kg +3.4 kg (0.83 m,0.58 m)

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