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What centripetal force does an 80-kg passenger experience when seated 12 m from the center of...

What centripetal force does an 80-kg passenger experience when seated 12 m from the center of a Ferris wheel whose angular speed is 0.50 rad/s?
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Answer #1
centripetal force = m r w ^ 2
where m = mass = 80 kg
           r= distance from center = 12 m
           w= angular speed = 0.5 rad / s
So, F = 240 N
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Answer #2
We know that,
Centripital Force,F = m*r*(w^2)

where ,
m= mass of body = 80kg
r = radius of circle = 12m
w = angular speed = 0.5 rad/s

putting all the values,
F = 80*12*(0.5^2) = 240N
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Answer #3
What centripetal force does an 80-kg passenger experience whenseated 12 m from the center of a Ferris wheel whose angular speedis 0.50 rad/s?
centripetal force=mrω*ω=80*12*0.5*0.5=240N
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