Question

Determine the values of the specified properties at each of the following conditions (a) For Refrigerant 134a at T= 60°C and v = 0.072 m3/kg, determine p in kPa, and h in kJ/kg p= h= (b) For ammonia at p = 20bar and v = 0.005 m3/kg, determine Tin kPa kJ/kg and u in kJ/kg oC kJ/kg -10°C and u T= u= (c) For Refrigerant 22 at T and v in m3/kg. 200 k /kg, determine p in bar bar m3/kg v=

Answer 1

Comment below in case of any doubt.

classmate Date Uusing Table 4-13 SupuheatdR13a at Ta 6o'C ond: 0.072 m3) p 320+ (0.072- 0-81)x (2100-32o 0-66110-0.08It P 362.855 kfa 301(0-072-0o)x 302.96-301 nswer h 3o4I1 o C0: 064104 -0 oI) h 303-494 kJIk 母ns Using bSaurated morvia [email protected] |T= 4g.37"c 1)f= 0.0017731 m3/kg uf= 414.44 kJl °C 1342 37 Ug-u 414-44t/o:005-о.001 7731 0.0644-0-001773 )X(1342-37-414.44 = y u 162.25 k

classmate Date Page = 0.0007606 m3/ K 0.0652 mk = 33.27 kJlk ラ1 +/200-33.27 )x(0-0652-о-o007606 1) = 0-000-7606 R33-02-33-27 1 |ク=0.05738 |m2ka