Question

Part A Constants In (Figure 1), each capacitor has C-375 μF and Vab 32.5V Calculate the charge on C1 Express your answer in microcoulombs to three significant figures. Figure 1 of 1 Submit uest Answer Part B Calculate the charge on C2 Cl Express your answer in microcoulombs to three significant figures. Q2 Submit uest Answer

Answer 1

C1 and C2 are in series. so, equivalent capacitance,

Cs = C*C / 2C = C / 2

This is in parallel with C3,

Cp = (C / 2) + C = 3C / 2

Cp is in series with C4,

Ceq = (3C / 2)*C / (3C / 2) + C

Ceq = 3C / 5

Net charge on system,

Q = Ceq * V = (3*3.75*10^-6 / 5) * 32.5

Q = 73.125 uC

Same charge is present on on Cp and C4.

Q4 = 73.125 uC

Potential across capacitor C4,

V4 = Q / C = 73.125 u / 3.75u

V4 = 19.5 V

Potential across Cp,

Vp = Q / Cp

Vp = 73.125 u / (3*3.75 u / 2) = 13 V

Same voltage is present across Cs and C3.

so, Q3 = C3 * Vp

Q3 = 3.75*10^-6 * 13

Q3 = 48.75 uC

Charge across Cs,

Qs = Cs * Vp = (3.75*10^-6 / 2) * 13

Qs = 24.37 uC

Charge on C1, Q1 = 24.37 uC

Charge Q2 = 24.37 uC

Potential across C1 and C2,

V1 = V2 = 24.37 u / 3.75 u

V1 = V2 = 6.5 V

(A)

Charge on C1, Q1 = 24.37 uC

(B)

Charge on C2, Q2 = 24.37 uC

(C)

Charge on C3, Q3 = 48.75 uC

(D)

Charge on C4, Q4 = 73.125 uC

(E)

Voltage difference across C1, V1 = 6.5 V

(F)

Voltage difference across C2, V2 = 6.5 V

(G)

Voltage difference across C3, V3 = 13 V

(H)

Voltage difference across C4, V4 =  19.5 V