a)
Density of water is 1 g/mL
So,
Mass of water = 100 g
Use:
(m/m)% = mass of sugar * 100 / mass of solution
= 5.3 * 100 / (5.3 + 100)
= 5.03 %
Answer: 5.03 %
b)
Use:
(m/m)% = mass of Ar * 100 / mass of solution
= 50.0 * 100 / (50.0 + 80.0)
= 38.5 %
Answer: 38.5 %
c)
Density of water is 1 g/mL
So,
Mass of water = 100 g
Molar mass of C6H12O6,
MM = 6*MM(C) + 12*MM(H) + 6*MM(O)
= 6*12.01 + 12*1.008 + 6*16.0
= 180.156 g/mol
use:
mass of C6H12O6,
m = number of mol * molar mass
= 0.1 mol * 1.802*10^2 g/mol
= 18.02 g
Use:
(m/m)% = mass of C6H12O6 * 100 / mass of solution
= 18.02 * 100 / (18.02 + 100)
= 15.3 %
Answer: 15.3 %
3. Calculate the concentration in % (m/m) of the following solution. a. 5.3 g of sugar...
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