Hey, please explain how to do part b and how to get the d of part c. The answer is incorrect, I thought it would be positive but that was not right either. Thank you!
Hey, please explain how to do part b and how to get the d of part...
please help A small mailbag is released from a helicopter that is descending steadily at 2.75 m/s. (a) After 5.00 s, what is the speed of the mailbag? v = -51.75 m/s (b) How far is it below the helicopter? d = 150 Your response differs from the correct answer by more than 10%. Double check your calculations, m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.75 m/s? v =...
A small mailbag is released from a helicopter that is descending steadily at 2.50 m/s. (a) After 3.00 s, what is the speed of the mailbag? v = (b) How far is it below the helicopter? d = (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.50 m/s? v = d =
A small mailbag is released from a helicopter that is descending steadily at 1.19 m/s. (a) After 5.00 s, what is the speed of the mailbag? v = 50.19 m/s Correct: Your answer is correct. m/s (b) How far is it below the helicopter? d = ??? Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 10%. Double check your calculations. m (c) What are your answers to parts (a) and (b) if the...
A small mailbag is released from a helicopter that is descending steadily at 2.38 m/s. (a) After 4.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.38 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.50 m/s. (a) After 3.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.50 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.14 m/s. (a) After 4.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.14 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.23 m/s. (a) After 4.00 s, what is the speed of the mailbag? (b) How far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.23 m/s?
50 Nelocity greater or less than the speed you calculate. 50. small mailbag is released from a helicopter that is descending steadily at 1.50 m/s. After 2.00 s, (a) what is the speed of the mailbag, and (b) how far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.50 m/s?
A small mailbag is released from a helicopter that is descending steadily at 1.11 m/s. (a) After 3.00 s, what is the speed of the mailbag? (b) How far is it below the helicopter in m? (c) What are the answers to parts (a) and (b) if the helicopter is rising steadily at 1.11m/s, in m/s and m respectively? A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.60 m/s2...
While riding in a hot air balloon, which is steadily descending at a speed of 1.12 m/s, you accidentally drop your cell phone. After 4.00 s, what is the speed of the cell phone? v= m/s How far is the cell phone below the balloon after this time? D = m What are your answers to parts (a) and (b) if the balloon is rising steadily at 1.12 m/s? v = m/s d = m