A small mailbag is released from a helicopter that is descending steadily at 1.11 m/s. (a) After 3.00 s, what is the speed of the mailbag? (b) How far is it below the helicopter in m? (c) What are the answers to parts (a) and (b) if the helicopter is rising steadily at 1.11m/s, in m/s and m respectively?
A record of travel along a straight path is as follows:
1. Start from rest with constant acceleration of 2.60
m/s2 for 10.0 s.
2. Maintain a constant velocity for the next 1.40 min.
3. Apply a constant negative acceleration of −9.13 m/s2
for 2.85 s.
(a) What was the total displacement for the trip?
(b) What were the average speeds for legs 1, 2, and 3 of the trip,
as well as for the complete trip?
If your query is been resolved please upvote,it takes alot of effort and time to solce each question please encourage the effort by upvote/like.
If you have any doubt or think that the answer is incorrect please comment it down below dont dislike/downvote,it really affect our ratings.
Tha ks and regards.
A small mailbag is released from a helicopter that is descending steadily at 1.11 m/s. (a)...
A small mailbag is released from a helicopter that is descending steadily at 1.23 m/s. (a) After 4.00 s, what is the speed of the mailbag? (b) How far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.23 m/s?
A small mailbag is released from a helicopter that is descending steadily at 2.50 m/s. (a) After 3.00 s, what is the speed of the mailbag? v = (b) How far is it below the helicopter? d = (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.50 m/s? v = d =
A small mailbag is released from a helicopter that is descending steadily at 2.38 m/s. (a) After 4.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.38 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.50 m/s. (a) After 3.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.50 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.14 m/s. (a) After 4.00 s, what is the speed of the mailbag? v = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.14 m/s? v = m/s d = m
A small mailbag is released from a helicopter that is descending steadily at 1.19 m/s. (a) After 5.00 s, what is the speed of the mailbag? v = 50.19 m/s Correct: Your answer is correct. m/s (b) How far is it below the helicopter? d = ??? Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 10%. Double check your calculations. m (c) What are your answers to parts (a) and (b) if the...
please help A small mailbag is released from a helicopter that is descending steadily at 2.75 m/s. (a) After 5.00 s, what is the speed of the mailbag? v = -51.75 m/s (b) How far is it below the helicopter? d = 150 Your response differs from the correct answer by more than 10%. Double check your calculations, m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.75 m/s? v =...
50 Nelocity greater or less than the speed you calculate. 50. small mailbag is released from a helicopter that is descending steadily at 1.50 m/s. After 2.00 s, (a) what is the speed of the mailbag, and (b) how far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.50 m/s?
i tried to follow the answer on here but i am no getting it. i can't follow what is being done A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.60 m/s2 for 18.0 s. 2. Maintain a constant velocity for the next 1.70 min. 3. Apply a constant negative acceleration of −9.12 m/s2 for 5.13 s. (a) What was the total displacement for the trip? (b) What were the...
record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.25 m/s2 for 14.0 s. 2. Maintain a constant velocity for the next 1.10 min. 3. Apply a constant negative acceleration of −9.33 m/s2 for 3.38 s. (a) What was the total displacement for the trip? (b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip? leg 1 m/s leg...