Question

A 15.07 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 14.73 grams of CO₂ and 3.017 grams of H₂O are produced.

In a separate experiment, the molar mass is found to be 90.04 g/mol. Determine the empirical formula and the molecular formula of the organic compound.

Furnace H2O absorber CO2 absorber Sample A 15.07 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 14.73 grams of CO2 and 3.017 grams of H20 are produced. In a separate experiment, the molar mass is found to be 90.04 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formular molecular formula =

Answer 1

- = 0.334272727 mol = moles of a moles of co. - 14.739 (mm = rngros) engl not moles of Ho 3.017 g MM = 188 (mod) 18 91 mol = 0.16761111 mol = moles of H mores of H = 2x0.1656|IIII = 0.335 222 222 moc 15: = 0.334772727 x 12+ 0.335 222222X1 + n X16 > no 15.07 -0.334772727 X/2) -0.335222222 16 0.709 219065 mol 11 mole ratio of c. H and o, C:H:0 = 0.3347727271033522222210.709219065 0.3347 J2 J29 0.335 2 2 2 2 2 2 0.209219065 03397727 270.33477 2727 0334772727 = 1:1.00 : 2:118509092 a 1:1:2 ( Empirical formula is CHOR) If molar mass - 90 on g/mol n (12 + 1 + 2X16) = 90104 >> n = goloy - 21000888889 € 2 i molecular formula is CHOy. 45