Question

Take σ = 1.16 x 10-10 cm2 and q : 1.06 x 10-11 C A pont charge g is near a uniformly charged, large flat surface of a dielectric (see the figure below). Find the electric field at P Measure the angle counterclockwise from the positive x axis.) magnitude direction +-10.0 cm 10,0 cm

Answer 1

The $E = \sigma /2\epsilon$ electric field at point P depends on the field due to the charged plate, and due to the point charge.

The field due to charged plate is

$E = \sigma /2\epsilon$

And due to point charge is

$\frac{1}{4pi\varepsilon } � \frac{q}{r^{2}}$

The values of the fields are,

6.55N/C

And

9.54N/C

The net Electric field is

E = 11.57N/C

And the direction is 304.48 degrees from the positive x axis , in the counter clockwise direction.