Question

Employers often use standardized measures to gauge how likely it is that a new employee with...

Employers often use standardized measures to gauge how likely it is that a new employee with little to no experience will succeed in their company. One such factor is intelligence, measured using the Intelligence Quotient (IQ). To show that this factor is related to job success, an organizational psychologist measures the IQ score and job performance (in units sold per day) in a sample of 10 new employees.

IQ Job Performance
100 16
115 39
108 22
98 20
120 44
147 53
132 43
85 59
105 29
110 38

(a) Convert the following data to ranks and then compute a Spearman correlation coefficient. (Round your answer to three decimal places.)
_______?

(b) Using a two-tailed test at a 0.05 level of significance, state the decision to retain or reject the null hypothesis.

Retain the null hypothesis

OR

Reject the null hypothesis.    

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Answer #1

I done all calculations by using Excel

H14 2 IQ JOB PERFOEMANCE RANK(IQ) RANK(JOB PERFORMANE) 100 115 108 98 120 147 132 85 105 110 16 39 0.418181818 0 10 7 n= 20 d.仁(n-2) 0.05 1.302118589 2.306004133 53 43 59 29 38 10 T STATISTIC- T CRITICAL= 10 10 61 12 13 14 15 16 17 18 SPEARMAN RANKCORRELATION= 0.418181818to calculate spearman rank correlation

first rank the two data sets the use formula CORREL(array1,array2)

array 1 is Rank(IQ), and array 2 is Rank (job performance)

Ho; There is no comes ation between Ta and To b performante 5 H,: There isCorelation ber uwean a and sob Pesformanse Hi under Ho test statistic is, 5 七 (1-3/(n-1) where 04113) 七 (1-10418)3181 /clo-n) vi teritical at oos leve of signif icanre こ 2.3060011 ca) t L tositic atos leve of signi ficante hypo Hhesis and d.f. There fore we Retain the noll しfain +o reject. the null hypo Heg ,5) nere torre- Uv e There is no correlation between q and Tob PerformanteT critical=TINV(0.05,d.f) in excel it gives us critical value.

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