The following equations relating the voltages across different resistors which are given below as :
# (4) V1 + (4) V2 = (90 V)
V1 = [(90 V) - (4) V2] / (4)
V1 = [(45 V) - (2) V2] / (2) { eq.1 }
# (2) V1 + (3) V2 + (6) V3 = (100 V)
(2) {[(45) - (2) V2] / (2) } + (3) V2 + (6) V3 = (100 V)
(45) - (2) V2 + (3) V2 + (6) V3 = (100 V)
(1) V2 + (6) V3 = [(100 V) - (45 V)]
(1) V2 + (6) V3 = (55 V) { eq.2 }
# (6.1) V2 + (7) V3 = (7.2 V) { eq.3 }
Equating eq.2 & 3, we get
(1) V2 + (6) V3 = (55 V) x 7
(6.1) V2 + (7) V3 = (7.2 V) x 6
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(7) V2 + (42) V3 = (385 V)
(36.6) V2 + (42) V3 = (43.2 V)
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- (29.6) V2 = (341.8 V)
V2 = - [(341.8 V) / (29.6)]
V2 = - 11.5 V
Inserting the value of 'V2' in eq.1, then we get
V1 = [(45 V) - (2) V2] / (2)
V1 = [(45 V) - (2) (-11.5 V)] / (2)
V1 = [(45 V) + (23 V)] / (2)
V1 = [(68 V) / (2)]
V1 = 34 V
You analyze the voltages across different branches of a simple circuit (using Kirchoff's Laws), and you...
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