Constants ▼ Part A A student bikes to school by traveling first dN = 1.10 miles...

Question

Question

Answer 1

Answer #1

Solution)

Here,

the first leg

dNx = 0; dNy = + 1.10 mi ......................(0 , 1.10)

the second leg

dWx = - 0.6 mi; dWy = 0 ...................(-0.6 , 0)

the third leg

dSx = 0; dSy = - 0.2 mi ......................(0 , -0.2)

then the displacement vector is

dN = ( -0.6 , (1.10- 0.2) )

dN = ( -0.6 , 0.9) (Ans)

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Answer 2

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