Question

3. (a) Calculate the magnitude and direction of the electric force on each of the three charges in the figure shown below. 6.00 C 1.50yC -2.00 μC 3.00 cm2.00 cm 3. (b) Determine the electric field at a point 1.00 cm to the right of the middle charge shown in the figure above. 3. (c) If a charge of -2.00 uC were placed at the point 1.00 cm to the left of the middle charge shown in the figure above, what would be the magnitude and direction of the force acting on it?

Answer 1

q_1 = 6 mu c (0, 0) q_2 = 1.5 mu c (3, 0) q_3 = -2 mu c (5, 0) (F^rightarrow_a_1)_net = k q_1 q_2 [r^rightarrow_1 - r^rightarrow_2]/ Vertical-bar r^rightarrow_1 - r^rightarrow_2 Vertical-bar ^3 + k q_1 q_3 [r^rightarrow_1 - r^rightarrow_3]/ Vertical-bar r^rightarrow_1 - r^rightarrow_3 Vertical-bar ^3 = 9 times 10^times 6 times 10^-6 times 1.5 times 10^-6 [- 3 i^]/1.3 i^l^3 times 10^-4 m^2 + 9 times 10^9 times 6 times 10^-6 times (- 2 times 10^-6) [- J i^]/1 - 5 i^1^3 times 10^-4 m^2 = -90 i^+ 43.2 i^= -46.8 i^N Vertical-bar F^rightarrow_q_1 Vertical-bar _net = 46.8 N Dir^n rightarrow to the left Direction D = tan^-1(0) = 0 degree theta = 0 degree (F^rightarrow_q_2)_net = times 10^9 times 1.5 times 10^-6 times 6 times 10^-6 [3 i^]/13 i^1^3 times 10^-4 m^2 + 9 times 10^9 times 1.5 times 10^-6 (- 2 times 10^-6) [- 2 i^]/ Vertical-bar - 2 i^ Vertical-bar ^3 times 10^-4 m^2 = 90 i^+ 67.5 i^= 157.5 i^N