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(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) N/C 6.00 μC 1.50pC -2.00 8.00 cm1 2.00 cm (b) If a charge of -2.31 uC is placed at this point, what are the magnitude and direction of the force on it? magnitude direction Submit Answer Save ProgressPractice Another Version
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a) electric field at given point is given by E electric field due to 6 uC+electric field due to (2uC)- electric field due to

b) F qE 2.31 10*-6* 2*1017 directed along - x axis 46.2 N do comment in case any doubt, will reply for sure. Goodluck

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