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What force is exerted on the water in an MHD drive utilizing a 50 cm diameter...

What force is exerted on the water in an MHD drive utilizing a 50 cm diameter tube, if 75 A current is passed across the tube that is perpendicular to a 1.25 T magnetic field?

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Answer #1

F = BI l Sino = 1.254 75+ 8.5 & Sin 90° - 146.875 Nenton

Using the formula, F = B×i×l×sin(theta)

Where B is magnetic field

i is current

l is length

Theta is angle

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