Question

How many grams of primary standard grade sodium carbonate are necessary to prepare 2.00 L of a 0.0480 M Na2CO3 solution? Number g

Answer 1

Molecular weight of Na₂CO₃ is almost 106.

Now according to the definition of molarity we can say that:

1000 ml 1 M solution of Na₂CO₃ contains = 106 gm of Na₂CO₃

So 2000 ml 0.0480 solution of Na2CO3 contains = (106 X 2000 X 0.0480) / 1000 = 10.176 gm.

So 10.176 grams of primary standard grade sodium carbonate are necessary to prepare 2.00 L of a 0.0480 M of Na₂CO₃ solution.