How many grams of the primary standard sodium carbonate, Na2CO3 (molar mass=105.99g/mol) is needed to react...

Question

Question

How many grams of the primary standard sodium carbonate, Na₂CO₃ (molar mass=105.99g/mol) is needed to react with 19.4 ml of 0.15 M HCL?

Answer 1

Answer #1

molarity = number of moles Na2CO3 / volume of solution in L

0.15 = number of moles Na2CO3 / 0.0194 L

number of moles of Na2CO3 = 0.00291 mole

number of moles of Na2CO3 = mass of Na2CO3 / molar mass of Na2CO3

0.00291 mole = mass of Na2CO3 / 105.99 g.mol^-

mass of Na2CO3 = 0.308 g

Therefore, the mass of Na2CO3 = 0.308 g

Answer 2

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