for water melon
initial velocity voy = 0
acceleration ay = -g
initial position yo = 320 m
at time t and position y
let the water melon passes the superman
y - yo = vy*t + (1/2)*ay*t^2
y - 320 = 0 - (1/2)*9.8*t^2 ............(1)
for super man
speed of v1 = -34 m/s
acceleration a1 = 0
initial position yo = 0
y - yo = v1*t + (1/2)*a1*t^2
y - 320 = -34*t...........(2)
from 1 and 2
-34*t = -(1/2)*9.8*t^2
time t = 6.94 m/s
at time t = 6.94 for water melon
vy = voy + ay*t
vy = 0 - 9.8*6.94 = -68.012 m/s
the speed of water melon = 68.012 m/s <<<<--------------answer
h2HW roblem 2.24 Part A Review How fast is the watermelon going when it passes Superman?...
As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens that Superman flies by at the instant you release the watermelon. Superman is headed straight down with a speed of 36.0 m/s. How fast is the watermelon going when it passes Superman?
As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens that Superman flies by at the instant you release the watermelon. Superman is headed straight down with a speed of 30.0 m/s How fast is the watermelon going when it passes Superman? Express your answer with the appropriate units.
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