Question

Aluminum iodide is a reagent used in synthetic organic chemistry. It can be prepared by reacting aluminum metal with solid iodine. If 168 g aluminum metal is reacted with 2,645 g iodine and the reaction proceeds in a 56.83% yield, what percent (by mass) of the remaining starting material is aluminum metal? Type your answer rounded to the first decimal place without units. Assume that the only reason the yield is not 100% is due to the fact that not all of the starting material reacted.

Answer 1

Page No. Date o 7 2 AlI Reaction : RAL + 3 I 2 Mass of A1= 26.98 : 2 A1 = 53.96 Given, 168 gm Aluminium reacted with 2645 9 & product yield - 56.83 % I z yield or Al - 56.83 x 168 - in gram 100 = 95.47 om Unreacted Aluminium = 72.53 gm (168-95. 47 m 7 168 = 95.47 - 53.96 g Aluminium neacted by mass = 53.96x95-47100 168 30.66 gm So percent (by mass of remaining starting material - 53.96- 30.66 23.3 m So 23.3 qm of aluminium is remaining by mass ..