CO (g) + 1/2 O2 (g) ⟶ CO2 (g) ΔH0rxn = -283 kJ/mol
CO moles required = 175 kJ / 283 kJ/mol = 0.6183745583 mol
CO molar mass = 28.01 g/mol
mass of carbon monoxide = 0.6183745583 mol x 28.01 g/mol = 17.3206713781 g
Answer: mass of carbon monoxide must be burned = 17.3 g
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