Question

The root mean square speed of H, molecules at 25 °C is about 1.6 km/s. What is the ro a N2 molecule at 25 °C? is about 1.6 km/s. What is the root mean square speed of Urms - 3 PT 2082 1273 +25

Answer 1

Following is the - complete Answer -&- Explanation: for the first question (i.e. Question - 1 ), of the given: Question Set.....in....typed format...

$\Rightarrow$Answer:

Mass of carbon monoxide ( CO ) , required to be burnt =  44.35 g (grams ) of carbon monoxide ( CO ), ( i.e. under standard state conditions...)

$\Rightarrow$Explanation:

Following is the complete Explanation: for the above: Answer, in....typed format...

• Given:

1. Heat produced by burning, given mass of carbon monoxide: CO = 175.0 kJ ( kilo - joule )

• ​​​​​​​Step - 1:

​​​​​​​We know the following:

1. Standard Heat of formation, of carbon monoxide: $\Delta$H_f^o [CO] = - 110.525 kJ / mol
2. We know: 1.0 mol of carbon monoxide ( CO ) : after burning would produce: 110.525 kJ of Heat ...
3. We know: molar mass: of carbon monoxide ( CO ) = 28.01 g /mol

• ​​​​​​​Step - 2:

​​​​​​​Therefore, we know the following:

$\Rightarrow$110.525 kJ of Heat is released by burning: 28.01 g ( grams ) of carbon monoxide ( CO )... therefore...

$\Rightarrow$175.0 kJ  of Heat will be released by burning: [ ( 28.01 g ) / ( 110.525 kJ ) ] x ( 175.0 kJ ) = 44.35 g ( grams ) of CO ...

Therefore:

• Answer:

​​​​​​​Therefore:

$\Rightarrow$44.35 g (grams ) of carbon monoxide ( CO ) , will have to be burnt to produce: 175.0 kJ ( kilo-joule) of Heat...under standard state conditions...