Question

(a) Compute the root-mean-square speed of a nitrogen molecule at 99.6°C. The molar mass of nitrogen molecules (N2) is 28.0x10-3 kg/mol. At what temperatures will the root-mean-square speed be (b) 1/3 times that value and (c) 2 times that value?

Answer 1

a) Temperature, t= 99.6°c. In Kelvin scale T=(273+99.6)k. 372-6 K. Molas 28.0x10m3 kg/mol. > mass, M So, Roms. speed, BRT m on, 3x 8.314 x 372-6 28.0 x103 on, os 57 6.1 m/s. by Let, أم be temperature Ron which is w/6 os, Эст Le g/m 닉 BRT' ga g on, 28.04103 T'a x me 576. (57 11 2FR 27 X 8. 314. Os, pla 4 1.4k.

in celcius t'= (I'=273)ºe. 231-6°C. e). Let, for the temperatuse' o'= 20. os, &' ."و BRT" 2v- 3RT" 2x BRT" BRT 2 TETT on, T" 4T 4x 372.6 on, T" 1490-4 k. 8 In Celcius t'= (I"-273 os, Ex 1217640 1