Question

Calculate the root mean square velocity, v_rms, of a molecule that has a molar mass, M, of 45.02 g/mol at a temperature of 40.56 °C using the equation below. For this calculation the gas constant, R, is expressed as 8.314 J/(mol*K) and the molar mass, M, needs to be converted to kg/mol.

$LaTeX: v_{rms}\:=\:\sqrt{\frac{3RT}{M}}$ vrms=3RTM

Answer 1

Given the campound molan mass = 45.02 9/mo 45.02 M 1 mol 45.02 X 10 1 mol = 45.02 x 10 K9mol Tempenaturs T (2.13 +40 56 313. 56 K The gas cns tant given - R =8.314 J K mol Noo we have he eauation that the 00t mean $24are veleeith 3 RT Vroms M

3 x 8.314 JK!my x 313.56 K Vnms 4 -3 Kg. m- 45. 02 x 10 - 2 X 313.56 3 x 8-314 K ms 45.02 x10-3 K JKg .m s2 m.s feun significaut tigures 416 8 0) 11

the noot mean the value Thus Sauare velocity Vre ms 4 l6 8 Ang D