Vrms=√3RT/M In this root mean square velocity formula, Why and Where does this '3' came from. Could you explain and give me a nice derivation.
Vrms=√3RT/M In this root mean square velocity formula, Why and Where does this '3' came from....
Please help me derive this equation 3RT 1.3 Derive the root-mean-square speed of a gas, Vrms = by applying the perfect
Calculate the root mean square velocity, vrms, of a molecule that has a molar mass, M, of 45.02 g/mol at a temperature of 40.56 °C using the equation below. For this calculation the gas constant, R, is expressed as 8.314 J/(mol*K) and the molar mass, M, needs to be converted to kg/mol. vrms=3RTM
What is the root mean square value of the following velocity components: 2.0 m/s, -3.0 m/s, and 4.0 m/s?
Suppose that the root-mean-square velocity Us of water molecules (molecular mass is equal to 18.0 g/mol) in a flame is Feedback found to be 1170 m/s. What temperature does this represent? The root-mean-square velocity Urms of a molecule in a gas is related to 5.95 x109 temperature the mass of the molecule m and the temperature of the gas T. 3KT Urms The Boltzmann constant is k = 1.38 x 10-23 J/K.
15. Calculate the root mean square velocity of helium gas at 295K. A) 42.9 m/s H- 2 B) 1360 m/s C) 135 m/s D) 4.26 m/s E) 892 m/s
4. Derive the expression for the root mean squared velocity of a gas from basic principles of mechanics. Explicitly list any assumptions that you make. Show that for an ideal gas PV = (1/3) n Mr v 2 ; n = number of moles, Mr = molecular mass and v = root mean square velocity
chem problem pls help Calculate the root mean square velocity in m/s of nitrogen gas molecules at 66 degrees Celsius. Round the answer to no decimal places. (Canvas cannot understand significant figures.)
There is this question that came in a quiz, it says: What does it mean when your TA asks you to ''balance your tubes'' Why is it important? My answer was: ''Is to balance the centrifuge machine by linning the tubes to balance the weight & thus the pressure would be equl and correct centrifugation would take place'' Unfotunately he deducted marks and noted me to provide more details. So, what could be a complete answer to that question. Regards,
In the theory of relativity, the mass of a particle with velocity v ism=mo/(square root ((1- v^ 2)/ c^2))where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
MATLAB WORK PLEASE The upward velocity of a rocket can be computed from the following formula: v=u* In mo -91 mo-91 where v = upward velocity, u = the velocity at which fuel is expelled relative to the rocket, me = the initial mass of the rocket at time t=0,9 = the fuel consumption rate, and g = the acceleration due to gravity. Compute the time tro at which v reaches an arbitrary value using the bisection method. Use the...